A can do a work in 24 days, B is 20% more efficient than A if C can do the work in 10 more days than B, find days taken by A and C together to complete the work.

1:

$320 $ days

2:

$344 $ days

3:

$340 $ days

4:

6 days

5:

None of these

A can do work in = 24 days

B is with 20% more efficiency, so B can do same work in = 20 days

C can do the same work in = 20 + 10 = 30 days

One day work of A and C

= $241 $ + $301 $

= 5 + $1204 $

= $1209 $

= $403 $

This has been asked in Question Paper

IBPS Clerk Prelims 2017

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