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Question Paper from: IIT JEE Main 2021 TestSeries Paper 1

If element A shows two cationic states +2 and +3 and form oxides in such a way that the ratio of the element showing +2 and +3 state is 1:3 in a compound. The formula of the compound will be.

A₈O₁₁

A₄O₁₁

A₉O₁₁

A₅O₁₁

Solution:

Chapter Name: Classification of Elements and Periodicity in Properties

Difficulty Level: Moderate

Let no of atoms in +2 is x

no of atoms in +3 is 3x

Hence charge on atom A is

2x + 3 [3x] = 11x

So net charge on oxygen is 11x

let the no of 'O' = y

charge on one 'O' = 2

2y = 11x

$y = \frac{11 x}{2}$

$A_{x} A_{3 x} O_{\frac{11 x}{2}}$

$A_{2 x} A_{6 x} O_{11 x}$

$A_{8} O_{11}$

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IIT JEE Main 2021 TestSeries Paper 1

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