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Question Paper from: IIT JEE Main 2021 TestSeries Paper 1

The mole fraction of glucose in an aqueous solution is 0.2 then the molality of the solution will be

13.8

55.56

Solution:

Chapter Name: Some Basic Concepts of Chemistry

Difficulty Level: Moderate

$m = \frac{X _{A}}{X _{B}} \times \frac{1000}{18}$

$= \frac{0.2}{0.8} \times 55.5$

= 13.8

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IIT JEE Main 2021 TestSeries Paper 1

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