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Question Paper from: IIT JEE Main 2021 TestSeries Paper 2

Glutamic acid H₂N-CH(CH₂ CH₂ COOH).COOH has $p K a_{1} (α - COO H) = 2.2, p K a_{2} (α - N H_{3}^{+}) = 9.8$ and $p K a_{3} (R g ro u pCOO H) = 4.3$ The isoelectric point of glutamic acid is

5.9

10.2

3.25

Solution:

Chapter Name: Biomolecules

Difficulty Level: Moderate

Glutamic acid is an acidic amino acid due to the 2COOH group and one NH₂ group.

In the case of an acidic amino acid

$P H_{I so l ec t r i c P o in t} = \frac{p K a _{1} ( α - COO H ) + p K a _{3} ( R g ro u p COO H )}{2}$

$= \frac{2.2 + 4.3}{2} = 3.25$

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IIT JEE Main 2021 TestSeries Paper 2

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