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Question Paper from: IIT JEE Main 2021 TestSeries Paper 2

If C-C bond energy is 348 KJmol^-1, C-H bond energy is 412 KJ mol^-1 and H-H bond energy is 436 KJ mol^-1, the Pauling electronegativity of C is about [Given Electronegativity of H = 2.1]

1.64

1.82

2.58

2.91

Solution:

Chapter Name: Classification of Elements and Periodicity in Properties

Difficulty Level: Moderate

Linus Pauling developed a method for the calculation of relative electronegative of an element in KJ mol-1

$X_{A} - X_{B} = 0.101 Δ E$

$Δ E = B o n d e n er g y o f (A - B) - B . E o f (A - A) \times B . E o f (B - B)$

A = Carbon

B = Hyderogen

$X_{C} - X_{H} = 0.101 B . E o f C - H - B . E o f C - C \times B . E o f H - H$

$= 0.101 412 - 348 \times 436$

$= 0.101 412 - 389.5$

$= 0.101 22.5$

$X_{C} - X_{H} = 0.101 \times 4.74 = 0.484$

$X_{C} = 0.484 + 2.1 = 2.58$

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IIT JEE Main 2021 TestSeries Paper 2

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