Question Paper from: IIT JEE Main 2021 TestSeries Paper 2

The vapour density of a volatile chloride of divalent metal is 59.5 and equivalent mass of the metal is

Solution:

Chapter Name: Some Basic Concepts of Chemistry

Difficulty Level: Moderate

Given that VD = 59.5

Molecular Weight = $2 \times V D = 2 \times 59.5 = 119$

M + 2Cl $\to$ MCl₂

Mass of metal $= 119 - 2 \times 35.5 = 48$

$∴ M_{e q u} = \frac{M o l ec u l a r W g t}{Va l e n cy F a c t or} = \frac{48}{2} = 24$

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