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Question Paper from: IIT JEE Mains Shift 2 25th July 2021

For the following ions, the correct order of their Bond order is

$O_{2}^{-}, O_{2}, O_{2}^{2 -}, O_{2}^{+}$

$O_{2}^{-} > O_{2} > O_{2}^{+} > O_{2}^{2 -}$

$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$

$O_{2}^{+} > O_{2} > O_{2}^{2 -} > O_{2}^{-}$

$O_{2}^{+} > O_{2}^{2 -} > O_{2} > O_{2}^{-}$

Solution:

Chapter Name: Chemical Bonding and Molecular Structure

Difficulty Level: Easy

According to molecular orbital theory

$B . O = \frac{1}{2} [N_{b} - N_{a}]$

$O_{2} = 2.0$

$O_{2}^{+} = 2.5$

$O_{2}^{-} = 1.5$

$O_{2}^{2 -} = 1.0$

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IIT JEE Mains Shift 2 25th July 2021

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