Length of the rectangle is 80% of diagonal of a square of area 1225, then find the area of a rectangle if it's perimeter is 94√2.

1:

1016

2:

500

3:

1604

4:

1064

5:

625

Area of square= 1225

a² = 1225

a = 35, diagonal of square = a√2 = 35√2

length of rectangle = 80% of 35√2

l = 28√2

Perimeter = 94√2

2(l+b) = 94√2

2l +2b = 94√2

2b = 94√2 − 56√2

2b = 38√2

b = 19√2

Area= l × b = 28√2×19√2

=1064

This has been asked in Question Paper

IBPS Clerk Prelims 2017

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