Length of the rectangle is 80% of diagonal of a square of area 1225, then find the area of a rectangle if it's perimeter is 94√2.
1016
500
1604
1064
625
Area of square= 1225
a² = 1225
a = 35, diagonal of square = a√2 = 35√2
length of rectangle = 80% of 35√2
l = 28√2
Perimeter = 94√2
2(l+b) = 94√2
2l +2b = 94√2
2b = 94√2 − 56√2
2b = 38√2
b = 19√2
Area= l × b = 28√2×19√2
=1064
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IBPS Clerk Prelims 2017
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