I. 3x² + 4x + 1=0
II. y² + 5y + 6= 0
x = y or no relation can be established.
x ≤ y
x ≥ y
x > y
x < y
3x² + 4x + 1 = 0
⇒ 3x² + 3x + x + 1 = 0
⇒ 3x(x + 1) + 1(x + 1) = 0
⇒ (x + 1)(3x + 1) = 0
x = -1,
y² + 5y + 6 = 0
⇒ y² + 3y + 2y + 6 = 0
⇒ y(y + 3) + 2(y + 3) = 0
⇒ (y + 3)(y + 2) = 0
⇒ y = -3, -2
x > y
This has been asked in Question Paper
SBI PO Prelims 2017
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